Convert btu (it) per pound fahrenheit to joule per kilogram kelvin instantly. Type in either field — results update live.
Selected BTU (IT)/(lb·°F) values converted to J/(kg·K) using the exact factor from this tool.
| BTU (IT)/(lb·°F) | J/(kg·K) |
|---|---|
| 0.01 | 41.868 |
| 0.1 | 418.68 |
| 1 | 4,186.8 |
| 2 | 8,373.6 |
| 3 | 12,560.4 |
| 5 | 20,934 |
| 10 | 41,868 |
| 20 | 83,736 |
| 50 | 209,340 |
| 100 | 418,680 |
| 1,000 | 4,186,800 |
Exact conversion factors in both directions, plus a worked example.
1 BTU (IT)/(lb·°F) = 4186.8 J/(kg·K)
1 J/(kg·K) = 0.0002388459 BTU (IT)/(lb·°F)
To convert btu (it) per pound fahrenheit to joule per kilogram kelvin, multiply by 4186.8.
To convert joule per kilogram kelvin to btu (it) per pound fahrenheit, multiply by 0.0002388459.
Example: convert 10 BTU (IT)/(lb·°F) to J/(kg·K)
10 × 4186.8 = 41868 J/(kg·K)
Short background on the units used in this conversion.
A BTU (IT) per pound Fahrenheit equals 4,186.8 J/(kg·K) — the imperial specific heat unit common in US HVAC and materials handbooks.
BTU (IT) per pound Fahrenheit describe building materials, refrigerants, and process fluids in US engineering references.
The joule per kilogram kelvin (J/(kg·K)) is the SI unit of specific heat capacity — energy required to raise one kilogram by one kelvin.
Joules per kilogram kelvin rate materials, fluids, and solids in engineering heat-transfer and energy storage calculations.
J/(kg·K) = BTU (IT)/(lb·°F) × 4,186.8BTU (IT)/(lb·°F) = J/(kg·K) × 0.0002388459, using the same exact factors as this converter.Jump to any specific heat capacity conversion starting from btu (it) per pound fahrenheit — including the reverse direction and every other unit in our dataset.