Convert calorie (it) per gram celsius to joule per kilogram kelvin instantly. Type in either field — results update live.
Selected cal (IT)/(g·°C) values converted to J/(kg·K) using the exact factor from this tool.
| cal (IT)/(g·°C) | J/(kg·K) |
|---|---|
| 0.01 | 41.868 |
| 0.1 | 418.68 |
| 1 | 4,186.8 |
| 2 | 8,373.6 |
| 3 | 12,560.4 |
| 5 | 20,934 |
| 10 | 41,868 |
| 20 | 83,736 |
| 50 | 209,340 |
| 100 | 418,680 |
| 1,000 | 4,186,800 |
Exact conversion factors in both directions, plus a worked example.
1 cal (IT)/(g·°C) = 4186.8 J/(kg·K)
1 J/(kg·K) = 0.0002388459 cal (IT)/(g·°C)
To convert calorie (it) per gram celsius to joule per kilogram kelvin, multiply by 4186.8.
To convert joule per kilogram kelvin to calorie (it) per gram celsius, multiply by 0.0002388459.
Example: convert 10 cal (IT)/(g·°C) to J/(kg·K)
10 × 4186.8 = 41868 J/(kg·K)
Short background on the units used in this conversion.
A calorie (IT) per gram Celsius equals 4,186.8 J/(kg·K) — the International Table calorie per gram per degree, often approximating water near room temperature.
Calories (IT) per gram Celsius appear in older chemistry references and food-energy adjacent thermal property tables.
The joule per kilogram kelvin (J/(kg·K)) is the SI unit of specific heat capacity — energy required to raise one kilogram by one kelvin.
Joules per kilogram kelvin rate materials, fluids, and solids in engineering heat-transfer and energy storage calculations.
J/(kg·K) = cal (IT)/(g·°C) × 4,186.8cal (IT)/(g·°C) = J/(kg·K) × 0.0002388459, using the same exact factors as this converter.Jump to any specific heat capacity conversion starting from calorie (it) per gram celsius — including the reverse direction and every other unit in our dataset.