Convert joule per kilogram kelvin to calorie (it) per gram celsius instantly. Type in either field — results update live.
Selected J/(kg·K) values converted to cal (IT)/(g·°C) using the exact factor from this tool.
| J/(kg·K) | cal (IT)/(g·°C) |
|---|---|
| 0.01 | 0.0000023885 |
| 0.1 | 0.0000238846 |
| 1 | 0.0002388459 |
| 2 | 0.0004776918 |
| 3 | 0.0007165377 |
| 5 | 0.0011942295 |
| 10 | 0.002388459 |
| 20 | 0.0047769179 |
| 50 | 0.0119422948 |
| 100 | 0.0238845897 |
| 1,000 | 0.2388458966 |
Exact conversion factors in both directions, plus a worked example.
1 J/(kg·K) = 0.0002388459 cal (IT)/(g·°C)
1 cal (IT)/(g·°C) = 4186.8 J/(kg·K)
To convert joule per kilogram kelvin to calorie (it) per gram celsius, multiply by 0.0002388459.
To convert calorie (it) per gram celsius to joule per kilogram kelvin, multiply by 4186.8.
Example: convert 10 J/(kg·K) to cal (IT)/(g·°C)
10 × 0.0002388459 = 0.002388459 cal (IT)/(g·°C)
Short background on the units used in this conversion.
The joule per kilogram kelvin (J/(kg·K)) is the SI unit of specific heat capacity — energy required to raise one kilogram by one kelvin.
Joules per kilogram kelvin rate materials, fluids, and solids in engineering heat-transfer and energy storage calculations.
A calorie (IT) per gram Celsius equals 4,186.8 J/(kg·K) — the International Table calorie per gram per degree, often approximating water near room temperature.
Calories (IT) per gram Celsius appear in older chemistry references and food-energy adjacent thermal property tables.
cal (IT)/(g·°C) = J/(kg·K) × 0.0002388459J/(kg·K) = cal (IT)/(g·°C) × 4,186.8, using the same exact factors as this converter.Jump to any specific heat capacity conversion starting from joule per kilogram kelvin — including the reverse direction and every other unit in our dataset.